Question

Y(s)=1/((s^2 +4s +3)*(s+1)) 的拉普拉斯逆变换是什么?

Answer 1

key:

Y(s)=1/((s^2 +4s +3)*(s+1)) =-1/4*1/(s+1)+1/2*1/(s+1)^2+1/4*1/(s+3)

y(t)=(1/4)e^(-3t)[2te^(2t)-e^(2t)+1]