Question

已知函数f(x)=x^5+px^3+qx-8,若f(-20=10,则f(2)=?

Answer 1

f(-2)=(-2)^5+p(-2)^3+q(-2)-8=10

-32-8p-2q=10+8=18

所以32+8p+2q=-18

f(2)=2^5+p*2^3+q*2-8

=32+8p+2q-8

=-18-8

=-26