脱式计算:1.29/30+41/42+55/56+71/72+89/90+109/110

2个回答

  • 计算:1、29/30+41/42+55/56+71/72+89/90+109/110

    =1-1/30+1-1/42+1-1/56+1-1/72+1-/90+1-/110

    =6-(1/30+1/42+1/56+1/72+1/90+1/110)

    =6-[(14/420+10/420)+(9/504+7/504)+(11/990+9/990)]

    =6-(2/35+2/63+10/99)

    =6-(4/45+10/99)

    =6-(44/495+50/495)

    =6-94/495

    =5右401/495

    2、23又5/6-11又7/12+19又9/20-7又11/30+5又13/42-3又15/56+1又17/72

    =23+5/6-(11+7/12)+19+9/20-(7+11/30)+5+13/42-(3+15/56)+1+17/72

    =23+5/6-11-7/12+19+9/20-7-11/30+5+13/42-3-15/56+1+17/72

    =(23-11+19-7+5-3+1)+(5/6-7/12)+(9/20-11/30)+(13/42-15/56)+17/72

    =27+1/4+1/12+1/24+17/72

    =27+(18+6+3+17)/72

    =27+44/72

    =27+11/18

    =27右11/18