圆心到(-2,2),(5,2)距离相等因此必在直线x=(-2+5)/2=3/2上
设圆心为(3/2,b)半径为r,则圆方程(x-3/2)²+(y-b)²=r²
(5,2),(1,4)代入有
(5-3/2)²+(2-b)²=r²
(1-3/2)²+(4-b)²=r²
b=0,r²=65/4
(x-3/2)²+y²=65/4
圆心到(-2,2),(5,2)距离相等因此必在直线x=(-2+5)/2=3/2上
设圆心为(3/2,b)半径为r,则圆方程(x-3/2)²+(y-b)²=r²
(5,2),(1,4)代入有
(5-3/2)²+(2-b)²=r²
(1-3/2)²+(4-b)²=r²
b=0,r²=65/4
(x-3/2)²+y²=65/4