2x²-ax-y+b-2bx²-3x-5y+1
=(2-2b)x^2-(a+3)x-6y+b+1
因为值与字母x的值无关
所以2-2b=0,-(a+3)=0
b=1,a=-3
3(a²-ab-b²)-4a²-ab-b²
=3a^2-3ab-3b^2-4a^2-ab-b^2
=-a^2-4ab-4b^2
=-(a+2b)^2
=-(1-6)^2
=-25
2x²-ax-y+b-2bx²-3x-5y+1
=(2-2b)x^2-(a+3)x-6y+b+1
因为值与字母x的值无关
所以2-2b=0,-(a+3)=0
b=1,a=-3
3(a²-ab-b²)-4a²-ab-b²
=3a^2-3ab-3b^2-4a^2-ab-b^2
=-a^2-4ab-4b^2
=-(a+2b)^2
=-(1-6)^2
=-25