题目中f(x)=6应该是 f(3)=6吧?如果是f(x)=6 则函数恒等于6 一条直线
f(x) = aX^3 - bsinX + 3
f(-x)=-aX^3 + bsinX + 3
f(-x) - 6 = -aX^3 + bsinX - 3 = -f(x)
f(-3) - 6 = -aX^3 + bsinX - 3 = -f(3)
f(-3) = -f(3) + 6 = 0
题目中f(x)=6应该是 f(3)=6吧?如果是f(x)=6 则函数恒等于6 一条直线
f(x) = aX^3 - bsinX + 3
f(-x)=-aX^3 + bsinX + 3
f(-x) - 6 = -aX^3 + bsinX - 3 = -f(x)
f(-3) - 6 = -aX^3 + bsinX - 3 = -f(3)
f(-3) = -f(3) + 6 = 0