由题意,f(x)=4x 2-4mx+m+2=0的两个根为x 1,x 2,
∴x 1+x 2=m, x 1 x 2 =
m+2
4
∴x 1 2+x 2 2= ( x 1 + x 2 ) 2 -2 x 1 x 2 = m 2 -
m+2
2 = (m-
1
4 ) 2 -
17
16
∵△=(4m) 2-16(m+2)≥0
∴m≥2或m≤-1
∴m=-1时,x 1 2+x 2 2取到最小值
1
2
故答案为:-1
由题意,f(x)=4x 2-4mx+m+2=0的两个根为x 1,x 2,
∴x 1+x 2=m, x 1 x 2 =
m+2
4
∴x 1 2+x 2 2= ( x 1 + x 2 ) 2 -2 x 1 x 2 = m 2 -
m+2
2 = (m-
1
4 ) 2 -
17
16
∵△=(4m) 2-16(m+2)≥0
∴m≥2或m≤-1
∴m=-1时,x 1 2+x 2 2取到最小值
1
2
故答案为:-1