2x^2-3x+2=0,2x^2+2=3x,x^2+1=3x/2
x^2+x^-2
=x^2+1/x^2
=(x^4+1)/x^2
=[(x^2+1)^2-2x^2]/x^2
=[(3x/2)^2-2x^2]/x^2
=[(1/4)x^2]/x^2
=1/4
2x^2-3x+2=0,2x^2+2=3x,x^2+1=3x/2
x^2+x^-2
=x^2+1/x^2
=(x^4+1)/x^2
=[(x^2+1)^2-2x^2]/x^2
=[(3x/2)^2-2x^2]/x^2
=[(1/4)x^2]/x^2
=1/4