Question

2x^2-3x+1=02x^2-4x+6=0(x+3)=(2x-1)^23(x+2)^2=x^2-43(x-2)^2=2

Answer 1

(2x-1)(x-1)=0

x1=1/2,x2=1

2(x-1)(x-2)=0

x1=1,x2=2

4x^2-5x-2=0

不能用因式分解

2x^2+12x+16=0

2(x+2)(x+4)=0

x1=-2,x2=-4

x^2-8x+12=0

(x-2)(x-6)=0

x1=2,x2=6

x^2-x-42=0

(x+6)(x-7)=0

x1=-6,x2=7