Question

已知（x²+x+1）分之x=4分之1,试求分式（x的4次方+x²+1）分之x²

Answer 1

（x²+x+1）分之x=4分之1

x/(x²+x+1)=1/4

4x=x²+x+1

4=x+1+1/x

3=x+1/x

9=(x+1/x)²

9=x²+2+1/x²

8=x²+1+1/x²

8x²=x^4+x²+1

x²/(x^4+x²+1)=1/8