先画出这个范围
z=2x+4y
y=-x/2+z/4
这是斜率-1/2的直线,
求出截距的最值即可
x+y=0,x=3,交点(3,-3)
x-y+5=0,x=3,交点(3,8)
从图上看出y=-x/2+z/4过这两点是截距有最值
(3,-3),z=-6
(3,8),z=38
所以最大38,最小-6
已知x,y满足x-y+5>=0,x+y>=0,x
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