Question

1:求由方程cos(x+y)+e^y=1所确定的隐函数y=f(x)的微分

Answer 1

对x求导数可以得到

-sin(x+y) * (1+y') + e^y * y' = 0

所以y'(e^x-sin(x+y)) = sin(x+y)

所以y' = sin(x+y) / (e^x-sin(x+y))