令t=(1-lnx)/(1+lnx)
得lnx=(1-t)/(t+1)
x=e^[(1-t)/(t+1)]
所以f(t)=(1-t)/(t+1)*e^[(1-t)/(t+1)]
即f(x)=(1-x)/(1+x)*e^[(1-x)/(1+x)]