12021042401240240
12+1+0+1+21+0+1+21+0+12+1+01+2+
1个回答
相关问题
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121*0.18+12.1*0.9-17*1.21
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(-16)*21/4-(-4)*(-21/2)*(-1)+(-8)*(-12)*(-0.125)
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计算:121×0.13+12.1×0.9-12×1.21=______.
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计算:121×0.13+12.1×0.9-12×1.21=______.
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121×0.18+12.1×0.9-17×1.21
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线性代数 正交法求标准型的问题Q=(n11 n12 n21)=1/√2 0 -1/√21/√2 0 -1√20 1 0为
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(0.1+0.21+0.31)*(0.21+0.31+0.41)-(0.1+0.21+0.31+0.41)*(0.21+
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利用因式分解进行计算(过程)121×0.13+12.1×0.9-12×1.21
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(1+0.228-0.21)*(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)*(0.
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直接写出得数.[1/2+12]= 1÷0.5= [1/7×21