4NH3(g)+5O2(g)=4NO(g)+6H2O(g)
1.7gNH3燃烧放出22.67KJ 现在方程式中4molNH3,则放出906.8KJ
4NH3(g)+5O2(g)=4NO(g)+6H2O(g) △H=-906.8KJ/mol