Question

解方程x²-a（2x-a+b）+bx-2b²

Answer 1

x2-a（2x-a+b）+bx-2b2

=x2-2ax+a2-ab+bx-2b2

=x2-(2a-b)x+a2-ab-2b2

=x2-(2a-b)x=(a+b)(a-2b)

=(x-(a+b))(x-(a-2b))

x=a+b x=a-2