Question

计算分式 x^2-1/y÷x+1/x^2

Answer 1

原式=[(x+1)(x-1)/y]/[(x+1)/((x^2)]

=[(x+1)(x-1)/y]*[(x^2)/(x+1)]

=[(x-1)/y]*(x^2)

=[(x-1)x^2]/y

=(x^3-x^2)/y

这一大串可是我用手机辛苦打的呀…