f(x)=x³+bx²+cx+2
f'(x)=3x²+2bx+c
x=1时f(x)=-1 ==> 1+b+c+2=-1 ==> b+c=-4
x=1时f'(x)=0 ==> 3+2b+c=0 ==> 2b+c=-3
解得 b=1,c=-5