Question

已知x^2+6xy+10y^2-2y+1=0.求x、y的值

Answer 1

x²+6xy+10y²-2y+1=0

x²+6xy+9y²+y²-2y+1=0

(x+3y)²+(y-1)²=0

y-1=0 y=1

x+3y=0 x=-3

x=-3 y=1