高中生物有关DNAJ计算题 若(A+T)/(A+T+G+C)=54%,G1/(A1+T1+G1+C1)=22%

3个回答

  • 若(A+T)/(A+T+G+C)=54%,得(G+C)/(A+T+G+C)=46%,在DNA双链中,由于A=T,G=C,所以双链上A+T与G+C的比值与每条单链上此碱基之和占该单链的比值是相等的,即(A1+T1)/(A1+T1+G1+C1)=(A2+T2)/(A2+T2+G2+C2)=54%,(G1+C1)/(A1+T1+G1+C1)=(G2+C2)/(A2+T2+G2+C2)=46%,由G1/(A1+T1+G1+C1)=22% 得C1/(A1+T1+G1+C1)=46%-22%=24%,根据碱基互补配对原则,G2/(A2+T2+G2+C2)=C1/(A1+T1+G1+C1)=24%.