Question

几道因式分解题^:几次方x^4+x^3+x^2-1x^4-3x^2+1x^4-7x^ ×2y^2+81y^4x^8+x^

Answer 1

x^4+x^3+x^2-1 = x^3(x+1) + (x+1)(x-1)=(x+1)(x^3+x-1)

x^4-3x^2+1 = x^4-2x^2+1-x^2 = (x^2-1)^2-x^2 =

(x^2+x-1)(x^2-x-1)

x^4-7x^ ×2y^2+81y^ 请确认题目

x^8+x^4+1 = x^8+2x^4+1-x^4=(x^4+1)^2-x^4 =

(x^4+x^2+1)(x^4-x^2+1)

2(x^2-3ab)+x(4a-3b) = 2x^2+(4a-3b)x-6ab =

(x+2a)(2x-3b)