Question

定义一种运算 1∧3=1*2+3 3∧1=3*2+1 3∧4=3*2+4 4∧3=4*2+3 那么计算[(x+y)∧(x

Answer 1

[(x+y)∧(x-y)]∧3x

=[(x+y)*2+(x-y)]^3x

=[3x+y]^3x

=[3x+y]*2+3x

=9x+2y