Question

函数y=Asin(wx+y)在同一周期内当x=-Pi/12时ymax=2当x=7Pi/12时ymin=-2则解析市为

Answer 1

最大最小之间是半个周期

所以T/2=(7+1)π/12

T=4π/3

|w|=2π/T=3/2

显然|A|=2

y=±2sin(±3/2x+φ)

若是y=2sin(3/2x+φ)

x=-π/12,y=2

3/2x+φ=π/2

φ=5π/8

若是y=2sin(-3/2x+φ)

x=-π/12,y=2

-3/2x+φ=π/2

φ=3π/8

若是y=-2sin(3/2x+φ)

x=-π/12,y=2

3/2x+φ=-π/2

φ=-3π/8

若是y=-2sin(-3/2x+φ)

x=-π/12,y=2

-3/2x+φ=-π/2

φ=-5π/8

y=2sin(3/2x+5π/8)

y=2sin(3/2x+3π/8)

y=-2sin(3/2x-3π/8)

y=-2sin(3/2x-5π/8)