Question

(x+2)^2=25 x^2-3x-1=0 9(2x+3)^2-4(2x-5)^2=0

Answer 1

(x+2)^2=25

x+2=5 x+2=-5

x=3或x=-7

x^2-3x-1=0

x=(3±√13)/2

x=(3+√13)/2 x=(3-√13)/2

9(2x+3)^2-4(2x-5)^2=0

9(2x+3)²=4(2x-5)²

3(2x+3)=2(2x-5) 3(2x+3)=-2(2x-5)

2x=-19 -10x=1

x=-19/2 x=-1/10