齐次方程组AX=0有基础解系,(1,-2,3,0,4)T,(-2,4,0,0,1)T,(3,-6,2,3,3)T,即
X=c1
1
-2
3
0
4+c2
-2
4
0
0
1+c3
3
-6
2
3
3=(3c1+2c3)
3
-6
1
0
0+3c3
齐次方程组AX=0有基础解系,(1,-2,3,0,4)T,(-2,4,0,0,1)T,(3,-6,2,3,3)T,即
X=c1
1
-2
3
0
4+c2
-2
4
0
0
1+c3
3
-6
2
3
3=(3c1+2c3)
3
-6
1
0
0+3c3