Question

a(a+1)(a+2)(a+3)+1 用平方差公式怎么做

Answer 1

a(a+1)(a+2)(a+3)+1

=[a(a+3)][(a+1)(a+2)]+1

=(a^2+3a)(a^2+3a+2)+1

=(a^2+3a)^2+2(a^2+3a)+1

=(a^2+3a+1)^2