设CxHy
CxHy + (y/2+2x)O2 → (y/2)H2O + xCO2
xCO2 = 9.9 g
M(CO2)=44g/mol
n(CO2)=9.9/44=0.225mol =x
M(C)=12
M(H)=1
y=(3.6-0.225*12)/1=0.9
∴x:y=90.225:0.=1:4
所以是
CH4
补充:
CH4是甲烷
设CxHy
CxHy + (y/2+2x)O2 → (y/2)H2O + xCO2
xCO2 = 9.9 g
M(CO2)=44g/mol
n(CO2)=9.9/44=0.225mol =x
M(C)=12
M(H)=1
y=(3.6-0.225*12)/1=0.9
∴x:y=90.225:0.=1:4
所以是
CH4
补充:
CH4是甲烷