∫ x^x(lnx+1) dx
let
y = x^x
lny = xlnx
(1/y) dy = (1 + lnx)dx
dy = (1+lnx) x^x dx
∫ x^x(lnx+1) dx
=∫ dy
=y + C
=x^x+ C
求解积分 ( x ^ x )( ln x + 1 )
∫ x^x(lnx+1) dx
let
y = x^x
lny = xlnx
(1/y) dy = (1 + lnx)dx
dy = (1+lnx) x^x dx
∫ x^x(lnx+1) dx
=∫ dy
=y + C
=x^x+ C