等差数列An 的前n项和Sn=n^2-9*n,第K项满足5
4个回答
1、
n>=2
S(n-1)=(n-1)²-9(n-1)=n²-11n+10
an=Sn-S(n-1)=2n-10
a1=S1=-8,也符合
5
相关问题
已知数列an的前n项和Sn=n^2-9n,第k项满足5
已知数列{an}的前n项和Sn=n^2-9n 第K项满足5
已知数列{An }的前 n项和Sn=nxn-9n ,第 k项满足5
已知数列﹛an﹜前n项和,Sn=n²-9n 第k项满足-5<ak<8、求k
数列 (12 13:19:3)数列{an}的前n项和为Sn=n2--9n,第K项满足5
已知数列{an}的前n项和Sn=n^2-9n,第k项满足5<ak<8,则k等于
已知数列{an}的前n项和Sn=n2-7n,若第k项满足9<ak<12,则k=______.
已知数列{an}的前n项的和Sn=n^2-16n,第k项满足6
若等差数列an的前n项和sn=(1+n)^2+k则k=?
等差数列已知等差数列{an}的前n项和为Sn,等差数列{bn}的前n项和为Tn,且Sn/Tn=5n-9/n=3,则使an