已知sin(π/4+a)=3/5,则sin2a=
1个回答
sin(π/4+a)=3/5,
cos(π/2+2a)=cos2(π/4+a)=1-2sin^2(π/4+a)=1-2*9/25=7/25
sin2a=-cos(π/2+2a)=-7/25
相关问题
已知sin(a+π/4)=1/3,a∈(π/2,π)则sin2a=
已知sin(a+π/4)=3/5,π/2<a≤3π/2,求sin(2a+π/4)
已知COS(A+π/4)=3/5,则SIN2A?
已知tana=2,则sin(π-a)cos(2π-a)sin(-a+3π/2)/tan(-a-π)sin(-π-a)=
已知a,b属于(3π/4,π),sin(a+b)=-3/5,sin(b-π/4)=12/13,则cos(a+4/π)=
已知cos(π/2+a)=2sin(a-π/2)求sin(π-a)+cos(a+π)/5cos(5π/2-a)+3sin
已知cosa=-5/13,a∈(π/2,π),则sin(a-π/3)=
已知α∈(π/2,π),sin(-a,-π)=8/17,则sin(a-3π/2)=?
已知-π/2<a<0,tan2α=-4/3,则[sin(a+π/6)]/[sin a+cos a]=?
已知sin(a-π)=2cos(2π-a),求(sin(π-a)+5cos(2π-a))/(3cos(π-a)-sin(