令2x²-6y²+3z²-xy+7xz+7yz=(x+ay+bz)(2x+cy+dz)
2x²-6y²+3z²-xy+7xz+7yz
=(x+ay+bz)(2x+cy+dz)
=2x²+acy²+bdz² +(2a+c)xy+(2b+d)xz+(bc+ad)yz
ac=-6
bd=3
2a+c=-1
2b+d=7
bc+ad=7
解得a=-2 b=3 c=3 d=1
2x²-6y²+3z²-xy+7xz+7yz=(x-2y+3z)(2x+3y+z)
2x^2-6y^2+3z^2-xy+7xz+7yz求次式待定系数法解法,
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