Question

2ax^4+5ax^3-13x^2-x^2+2010+2x+bx^3-bx^4+3x^3 是二次多项式,

Answer 1

由题意可知,

x的3、4次项系数为0,

即2a-b=0,5a+b+3=0,

解得a=-3/7,b=-6/7,

a^2+b^2=9/49+36/49=45/49.