lim(x→0,y→1)(1-xy)/(x2+y2)=1/1=1
求lim(x→0,y→1)(1-xy)/(x2+y2)=____
1个回答
相关问题
-
求下列各极限 lim(x,y)→(0,1) (2-xy)/(x^2+2y)
-
求lim(x,y)~(0,1)1-xy/x^2+y^2的极限,要详解
-
1,lim(x,y)→(0,0)xy/2-√(4-xy) 2,lim(x→0)1/x^2∫(0→x)(e^t-1)dt
-
求二重极限lim[xy/(1+x^2+y^2)],x→0,y→0.求详细步骤
-
求极限lim(1-2xy)/(x^2+y^2) x趋向于0 y趋向于1
-
当x→0 y→1时 求lim(1-xy)/x²+y²
-
2元函数求极限lim(x-0,y-0)xy/(x^2+y^2)极限
-
x^2+y^2-xy+2x-y+1=0,求X Y .
-
已知|x‐1|+(y-1)²=0 .求代数式(x²+4xy-2y²)-(x²+y)-2(y²+xy
-
lim(x→0)(3xy/(x^2+y^2))