an=a1+(n-1)d
bn=b1*d^(n-1)
因a1=b1,a4=b4
a1+3d=a1*d^3,a1=3d/(d^3-1)
又a10=b10,a1=9d/(d^9-1)
∴1/(d^3-1)=3/(d^9-1)
因d≠1,所以d=-2^(1/3)
a1=2^(1/3),b16=an,
n=32
an=a1+(n-1)d
bn=b1*d^(n-1)
因a1=b1,a4=b4
a1+3d=a1*d^3,a1=3d/(d^3-1)
又a10=b10,a1=9d/(d^9-1)
∴1/(d^3-1)=3/(d^9-1)
因d≠1,所以d=-2^(1/3)
a1=2^(1/3),b16=an,
n=32