Solution:∵geometric progreesion formula is S=a(1-q^n)/1-q. a is first term,q is
common ratio, n is term.
But in this question"its sum to infinity is 15",
So ( 见图片 )
∴ S=a/(1-q)
15=10/(1-q)
So q=-1/2
所以a3=aq^2
=10×(-1、2)^2
5/2
Solution:∵geometric progreesion formula is S=a(1-q^n)/1-q. a is first term,q is
common ratio, n is term.
But in this question"its sum to infinity is 15",
So ( 见图片 )
∴ S=a/(1-q)
15=10/(1-q)
So q=-1/2
所以a3=aq^2
=10×(-1、2)^2
5/2