动能=0.5mv^2=0.5×6×10^3×80^2=1.92×10^7 J
由牛顿第二定律求出加速度:ma=推力-阻力=F-0.02mg 求得加速度a=F/m-0.02g=2×10^4/(6×10^3)-0.02×10=3.13 m/s^2
滑行距离=0.5at^2=0.5a(v/a)^2=0.5v^2/a=1022.36m
动能=0.5mv^2=0.5×6×10^3×80^2=1.92×10^7 J
由牛顿第二定律求出加速度:ma=推力-阻力=F-0.02mg 求得加速度a=F/m-0.02g=2×10^4/(6×10^3)-0.02×10=3.13 m/s^2
滑行距离=0.5at^2=0.5a(v/a)^2=0.5v^2/a=1022.36m