Question

已知a、b为整数,关于x的一元一次方程2x-[2-(2b-1)x]=a-2与(2b-1)x+3=7-[(2-b)x+3]

Answer 1

2x-[2-(2b-1)x]=a-2

2x-2+(2b-1)x=a-2

(2+2b-1)x=a

x=a/(2b+1)

(2b-1)x+3=7-[(2-b)x+3]

（2b-1）x+3=7-(2-b)x-3=4-(2-b)x

[（2b-1）+(2-b)]x=1

x=1/(b+1)

所以a/(2b+1)=1/(b+1)

得ab=2b-a-1