设M(x,y)
√[(x+4)²+y²]=2√[(x-2)²+y²]
x²+8x+16+y²=4(x²-4x+4+y²)
3x²+3y²-24x=0
x²-8x+y²=0
(x-4)²+y²=16
∴动点M的轨迹方程是