Question

y=sinα/1+cosα的周期

Answer 1

y=(sina)/(1＋cosa)

=[2sin(a/2)cos(a/2)]/[1＋2cos²(a/2)－1]

=[2sin(a/2)cos(a/2)]/[2cos²(a/2)]

=[sin(a/2)]/[cos(a/2)]

=tan(a/2)

周期是π/(1/2)=2π