∵q=2,
∴
a 2 +3 a 4 +5 a 7
a 4 +3 a 6 +5 a 9 =
a 1 q+3 a 1 q 3 +5 a 1 q 6
a 1 q 3 +3 a 1 q 5 +5 a 1 q 8
=
a 1 q+3 a 1 q 3 +5 a 1 q 6
q 2 (a 1 q+3 a 1 q 3 +5 a 1 q 6 ) =
1
q 2 =
1
4 .
故答案为:
1
4 .
∵q=2,
∴
a 2 +3 a 4 +5 a 7
a 4 +3 a 6 +5 a 9 =
a 1 q+3 a 1 q 3 +5 a 1 q 6
a 1 q 3 +3 a 1 q 5 +5 a 1 q 8
=
a 1 q+3 a 1 q 3 +5 a 1 q 6
q 2 (a 1 q+3 a 1 q 3 +5 a 1 q 6 ) =
1
q 2 =
1
4 .
故答案为:
1
4 .