m4+m2+1=m4+_-m2+1=(m2+_)(

m4+m2+1=m4+_-m2+1=(m2+_)(m2+_)

1个回答

(m+2/m^2-2m)-(m-1)/(m^2-4m+4)除以m-1/m,其中m=4
计算:(2m+1/2)(4m-1)(4m∧2-1/4)-4m∧2(2m+1)(2m-1)
(m2-1/2m+1/4)(m2+1/2m+1/4)(m-1/2)(m+1/2)=?(过程）
化简：[(4m)/(m^2-4)+(m-2)/(m+2)]/1/(m^2-4)
1/m(m+2)+1/(m+2)(m+41/m(m+2)+1/(m+2)(m+4)+…+1/(m+2014)(m+201
(1)M^2+M-3M^2-5M+2M^2+4=?(M=-3/4)
解：“(m-2/m+2+4m/m²-4)÷1/4-m²
已知m+1/m=4,求(1)m^2+1/m^2 (2)(m-1/m)^2
化简求值：(-m^4/m^2)^2+(-2m)^3*m^2+(-m^2)^4/m^4,其中m=-1
(3m-1)^2-4m(2m-1)=1我哪儿错了?.(3m-1)^2-4m(2m-1)=1,9m^2+1-6m-(8m^