2(甲+乙/3)/3 = 2乙/3+22 = 44+(甲+乙/3)/3
2(甲+乙/3) = 2乙+66 = 132+(甲+乙/3)
2甲+乙2/3 = 2乙+66 = 132+甲+乙/3
甲 = 132-乙/3
2甲 = 4乙/3+66
132= 乙+33
乙=99
甲=99
丙=66
那么甲原有糖豆99粒豆
2(甲+乙/3)/3 = 2乙/3+22 = 44+(甲+乙/3)/3
2(甲+乙/3) = 2乙+66 = 132+(甲+乙/3)
2甲+乙2/3 = 2乙+66 = 132+甲+乙/3
甲 = 132-乙/3
2甲 = 4乙/3+66
132= 乙+33
乙=99
甲=99
丙=66
那么甲原有糖豆99粒豆