计算(a+3)(a-1)-a(a-2)
2个回答
(a+3)(a-1)-a(a-2)
=a^2+3a-a-3-a^2+2a
=4a-3
相关问题
计算:1/(a+3)+2a/(a-1)-(3a+5)/(a^2+2a-3)
计算:a^3/(a-1)-a^2-a-1=
计算a^3/a-1-a^2-a-1
计算:1/3a-(1/3a +2a)
计算:(a+3)(a-1)+a(a-2)
计算:(a+1a2−a−4a2−1)÷a2+2a−3a+3.
(1)计算:(a-2)2-a(a-3);
(a+1)(a+2)(a-3)计算
计算 3(2a+1)(2a-1)-4(3a-2)(3a+5)=
计算(3a+2)(3a-2)-5a(a-1)-(2a-1)的平方