10道因式分解10道关于因式分解的题

1个回答

  • a∧2x+a∧2y

    =(a^x)^2+(a^y)^2

    =(a^x+a^y)^2-2x^(x+y)

    =16-4

    =12

    a∧3x+a∧3y

    原式=(a^x+a^y)[(a^x)^2-a^xa^y+(a^y)^2]

    =4[12-a^(x+y)]

    =4(12-2)

    =40

    2(x+y)^2-5(x+y)(x-y)+3(x-y)^2

    原式=(2x+2y-3x+3y)(x+y-x+y)

    =(-x+5y)2y

    =-2y(x-5y)

    3㎡-7m-6

    =3㎡+2m-9m-6

    =m(3m+2)-3(3m+2)

    =(3m+2)(m-3)

    x^2-10xy+25y^2-6x+30y+8

    =(x-5y)^2-6(x-5y)+8

    =(x-5y)^2-2(x-5y)-4(x-5y)+8

    =(x-5y)(x-5y-2)-4(x-5y-2)

    =(x-5y-4)(x-5y-2)

    -b^2+7b-6?

    =-(b^2-7b+6)

    =-(b-1)(b-6)

    12a^2-12ab+3b^2

    =3(4a^2-4a+b^2)

    =3(2a-b)^2

    =3*(1/3)^2

    =1/3

    (a-b)(m+n)-(n-m)(b-a)

    =(a-b)(m+n)+(n-m)(a-b)

    =(a-b)(m+n+n-m)

    =2n(a-b)

    4x的平方y的平方-(x的平方+y的平方)的平方

    =-[(x^2+y^2)^2-4x^2y^2]

    =-[(x^2+y^2-2xy)(x^2+y^2+2xy)]

    =-(x-y)^2(x+y)^2

    (x-y-z)(x+y-z)-(y-z-x)(y+z-x)

    =(x-z-y)(x-z+y)-(y-x-z)(y-x+z)

    =(x-z)^2-y^2-(y-x)^2+z^2

    =(x-z)^2-(y-x)^2+z^2-y^2

    =(x-z+y-x)(x-z-y+x)+(z-y)(z+y)

    =(y-z)(2x-z-y)-(y-z)(z+y)

    =2(y-z)(x-y-z)