A+B+C=90°时,tanA*tanB+tanA*tanC+tanB*tanC=1
证明:
∵A+B+C=90°,C=90°-A-B
∴tanA*tanB+tanA*tanC+tanB*tanC=tanA*tanB+(tanA+tanB)*tan^(-1)(A+B)
=tanA*tanB+(tanA+tanB)(1-tanA*tanB)/(tanA+tanB)=tanA*tanB+1-tanA*tanB
=1
A+B+C=90°时,tanA*tanB+tanA*tanC+tanB*tanC=1
证明:
∵A+B+C=90°,C=90°-A-B
∴tanA*tanB+tanA*tanC+tanB*tanC=tanA*tanB+(tanA+tanB)*tan^(-1)(A+B)
=tanA*tanB+(tanA+tanB)(1-tanA*tanB)/(tanA+tanB)=tanA*tanB+1-tanA*tanB
=1