Question

2道初二分式计算1.a^(n+1)-6a^n+9a^(n-1)2.a^(n+1)-4a^n+4a^(n-1)这两个怎么分

Answer 1

1.a^(n+1)-6a^n+9a^(n-1)

=a^(n-1)(a^2-6a+9)

=a^(n-1)(a-3)^2

2.a^(n+1)-4a^n+4a^(n-1)

=a^(n-1)(a^2-4a+4)

=a^(n-1)(a-2)^2