计算(1+1/1×2)+(2+1/2×3)+(3+1/3×4)+……+(20+1/20×21)
1个回答
原式=(1+2+……+20)+(1/1*2+1/2*3+……)
=((1+20)*20/2)+(1/1-1/2+1/2-1/3+……)
=210+1-1/21
=210+20/21
相关问题
计算:(1+[1/1×2])+(2+[1/2×3])+(3+[1/3×4])+…+(20+[1/20×21]).
1/1×2×3+1/2×3×4+、、、+1/20×21×22=?
计算:24×(1/2×3+1/4×5+……+1/(20×21))
巧算:1/1×2+1/2×3+1/3×4+.+1/19×20+1/20×21
1/1×2×3+1/2×3×4+1/3×4×5+.1/20×21×22解答
1×2+2×3+3×4...+19×20+20×21=(分数)
『『『火速』』』初一数学题~1/1×2×3+1/2×3×4+1/3×4×5……+1/20×21×22
简便计算:1/1×3+1/2×4+1/3×5+.+1/18×20
计算(-1)×2×3×4,(-1)×(-2)×3×4,(-1)×(-2)×(-3)×4,(-1)×(-2)×(-3)×(
1\1×3 + 1\2×4+ 1\3×5 …… +1\18×20