Question

帮我做几道超难的数学题.1.若2x+5y-3=0,求 4的x次方 × 32的y次方 2.已知：2的x次方 = 4的y+1

Answer 1

1 4^x*32^y=2^(2x)*2^(5y)=2^(2x+5y)=2^3=8

2 2^x=4^(y+1)=2^(2y+2)===>>x=2y+2

27^y=3^(x-1)===>>3^(3y)=3^(x-1)=====>>>3y=x-1

x=2y+2 3y=x-1 两式联立 得x=4 y=1

3 a^3=-27*x^9*y^3*z^6=(-3)^3*(x^3)^3*(y)^3*(z^2)^3=(-3*x^3*y*z^2)^3===>>>>得到a=-3*x^3*y*z^2

4 （a*b^3）^2n=a^2n*b^6n=[a^2n]*[(b^3n)^2]=1/2013*2013^2=2013

5 3^(x+1)*2^x-3^x*2^(x+1)=2^2*3^2

左边=3*3^x*2^x-2*3^x*2^x=3^x*2^x=6^x=右边=6^2===>>>x=2