Question

计算：(1/x-3)+(1-x/6+2x)-(6/x^2-9)

Answer 1

(1/x-3)+(1-x/6+2x)-(6/x^2-9)

=[2(x+3)+(1-x)(x-3)-6*2]/2*(x^2-9)

=(2x+6-x^2+4x-3-12)/2*(x^2-9)

=(-x^2+6x-9)/2*(x^2-9)

=-(x-3)^2/2*(x+3)(x-3)

=-(x-3)/2*(x+3)

=(3-x)/(2x+6)