m=0.15*24 + (0.35-0.15)*27 = 9 g
c(NaOH)=(0.35-0.15)/(0.240-0.200) = 5 mol/L
c(H2SO4)= 5*200/500*2 =1mol/L
V=22.4*(0.15+1.5*0.2)=10.08L
m=0.15*24 + (0.35-0.15)*27 = 9 g
c(NaOH)=(0.35-0.15)/(0.240-0.200) = 5 mol/L
c(H2SO4)= 5*200/500*2 =1mol/L
V=22.4*(0.15+1.5*0.2)=10.08L